X-mas is the time to crack nuts. At least that's what normal people do. But mathematicians enjoy cracking very peculiar nuts, like the following one. Show that the equation below is true for every positive integer.

\sum_{k=0}^n\left\(\begin{array}{c}2n+1\\2k+1\end{array}\right\)(2k+1)\:=\:2^{2n-1}(2n+1).

As always in maths, the slogan is short is beautiful, i.e., you should find a solution that is as short and elegant as possible, without using much computations. For this exercise ou may get inspiration from Santa Claus who has to distribute gifts into ChristmasStockings...